10x^2=1620

Solution for 10x^2=1620 equation:

10x^2=1620

We move all terms to the left:

10x^2-(1620)=0

a = 10; b = 0; c = -1620;
Δ = b2-4ac
Δ = 02-4·10·(-1620)
Δ = 64800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{64800}=\sqrt{32400*2}=\sqrt{32400}*\sqrt{2}=180\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-180\sqrt{2}}{2*10}=\frac{0-180\sqrt{2}}{20}
=-\frac{180\sqrt{2}}{20}
=-9\sqrt{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+180\sqrt{2}}{2*10}=\frac{0+180\sqrt{2}}{20}
=\frac{180\sqrt{2}}{20}
=9\sqrt{2}
$